When heated, mercuric oxide decomposes to form liquid mercury and oxygen. A scientist heated 10 grams (g) of mercuric oxide and formed 9.3 grams of liquid mercury. How many grams of oxygen were formed? A. 0.7 g B. 9.3 g C. 10.0 g D. 19.3 g

Respuesta :

According to the Law of conservation of mass, the grams of oxygen formed are A) 0.7 g.

Explanation:

According to the Law of conservation of mass, the total mass of the products in a chemical reaction must be equal to the total mass of the reactants.

In this problem, the chemical reaction is:

[tex]HgO \rightarrow Hg + O[/tex]

where

[tex]HgO[/tex] is the mercuric oxide

Hg is the liquid mercury

O is the oxygen

We have the following data:

[tex]m(HgO) = 10 g[/tex] (mass of mercuric oxide)

[tex]m(Hg) = 9.3 g[/tex] (mass of liquid mercury)

Since the mass of the products must be equal to the mass of the reactant (the HgO), we can find the mass of the oxygen produced:

[tex]m(O) = m(HgO)-m(Hg)=10 g - 9.3 g = 0.7 g[/tex]

Learn more about the Law of conservation of mass here:

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