Two planes leave the same airport at the same time. One flies at 20° east of north at 300 miles per hour. The second flies at 40° east of south at 400 miles per hour. How far apart are the planes after 2 hours? (Round your answer to the nearest mile.)

Respuesta :

This is a side - angle - side problem, solve using the law of cosines:

a^2 = 600^2 + 800^2 - 2*600*800*cos(120)

a = 1216.55 = 1,217 miles apart.

After 2 hours  approximately distance between planes were 1217miles.

What is distance?

" Distance is defined as the length between two end points in one dimension."

Formula used

Cosine law

[tex]a^{2} =b^{2} + c^{2} -2bc cos A[/tex]

According to the question,

Plane 1 moves 20° east of north at 300 miles per hour

1 hour = 300 miles

2 hour = 600 miles

Plane 2 moves 40° east of south at 400 miles per hour

1 hour = 400 miles

2 hour = 800 miles

As shown in the diagram drawn we have,

Angle between two planes in 120°.

Substitute the value in cosine law to get the distance between planes,

    [tex]a^{2} =(600)^{2} + (800)^{2} -2(600)(800) cos 120\°[/tex]

⇒[tex]a^{2} =360,000 +640,000 -(960,000)(\frac{-1}{2} )[/tex]

⇒[tex]a^{2} =1,480,000[/tex]

⇒[tex]a= 1216.55[/tex] miles

a ≈ 1217 miles (approximately)

Hence, after 2 hours  approximately distance between planes were 1217miles.

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