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A 29 kg box rests on the back of a truck. The coefficient of static friction between the box and the truck bed is 0.234. The acceleration of gravity is 9.81 m/s 2 . What maximum acceleration can the truck have before the box slides backward?

Respuesta :

Answer:

maximum acceleration will be [tex]2.295m/sec^2[/tex]        

Explanation:

We have given that mass of the box m = 29 kg

Coefficient of static friction [tex]\mu =0.234[/tex]

Acceleration due to gravity [tex]g=9.7m/sec^2[/tex]

For maximum acceleration [tex]\mu mg=ma[/tex]

[tex]a=\mu g[/tex]

So acceleration will be [tex]a=\mu g=0.234\times 9.81=2.295m/sec^2[/tex]

So maximum acceleration will be [tex]2.295m/sec^2[/tex]

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