Answer:
0.4118 mol
Explanation:
molar mass of CH3COOH = 12*2 + 4*1 +16*2 = 24+4+32= 60 g/mol
24.71 g / 60 (g/mol) = 0.4118 mol
Answer:
0.41 moles of acetic acid
Explanation:
moles are calculated as the division of compound mass by compound molar weight, that is:
moles of acetic acid = mass of acetic acid/ molar weight of acetic acid
The mass of acetic acid is 24.71 g and its molar weight is 2*12 + 4*1+ 2*16 = 60 g/mol, so
moles of acetic acid = 24.71/60 = 0.41 moles
