What is the equation of the line, in general form, that passes through the point (1.1) and has a y intercept of 2
x-y+2=0
x + y 2=0
x-y-2
=0
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Respuesta :

The equation of the line in the general form is x + y - 2 = 0 ⇒ 2nd answer

Step-by-step explanation:

The general form of the equation of a line is Ax + By + C = 0,where

  • A, B, and C are integers
  • The slope of the line is [tex]m=\frac{-A}{B}[/tex]
  • The y-intercept is [tex]\frac{-C}{B}[/tex]

∵ The line passes through point (1 , 1)

- Substitute x and y in the form of the equations by the coordinates

  of the point

∵ Ax + By + C = 0

∵ x = 1 and y = 1

∴ A(1) + B(1) + C = 0

A + B + C = 0 ⇒ (1)

∵ The y-intercept is 2

- That means the line intersects the y-axis at point (0 , 2)

∴ The line passes through point (0 , 2)

∵ x = 0 and y = 2

∴ A(0) + B(2) + C = 0

∴ 2B + C = 0

- Subtract 2B from both sides

C = -2B ⇒ (2)

Substitute (2) in (1)

∴ A + B + (-2B) = 0

∴ A + B - 2B = 0

∴ A - B = 0

- Add B to both sides

A = B

In the equation the coefficients of x and y are equal and C is twice

negative the coefficient of y

Let us look for the equation which has these conditions above

In the equation x + y - 2 = 0

∵ A = 1

∵ B = 1

∵ C = -2

∴ A = B and C = -2B

∴ The equation of the line is x + y - 2 = 0

The equation of the line in the general form is x + y - 2 = 0

Learn more:

You can learn more about the equation of a line in brainly.com/question/12941985

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