Respuesta :
Answer:
2.13 ft x 2.13 ft x 2.66 ft
Step-by-step explanation:
If W is the width of the square base, and H is the height, then:
12 = W²H
The cost of the crate is:
C = 8W² + 2W² + 4(4WH)
C = 10W² + 16WH
Solve for H in the first equation:
H = 12 / W²
Substitute into the second equation:
C = 10W² + 16W (12 / W²)
C = 10W² + 192 / W
Take the derivative with respect to W.
dC/dW = 20W − 192 / W²
Set to 0 and solve:
0 = 20W − 192 / W²
20W = 192 / W²
20W³ = 192
5W³ = 48
W = ∛(48/5)
W ≈ 2.13 ft
Find H:
H = 12 / W²
H ≈ 2.66 ft
Answer:
 2.125 ft square by 2.657 ft high
Step-by-step explanation:
Let x represent the side length in feet of the square base. Then the height is found from ...
 V = Bh
 V/B = h = 12/x²
The cost of material is the sum of costs of top, bottom, and sides. That is ...
 cost = 8x² +2x² +4(4xh) = 10x² +192/x
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The cost is minimized when its derivative with respect to x is zero.
 d(cost)/dx = 20x -192/x² = 0
 x³ = 9.6 . . . . . . multiply by x²/20 and add 9.6
 x = ∛9.6 ≈ 2.125 . . . . feet
 h = 12/x² ≈ 2.657 . . . . feet
The dimensions of the crate are 2.125 feet square by 2.657 feet high.
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Comment on the answer
You may notice that the cost of top and bottom together is $10 per square foot. The cost of opposite sides together is $8 per square foot. That is, the ratio of costs is ...
 base : sides = 10 : 8
You may also notice that the ratio of dimensions is ...
 height : base side = 2.657 : 2.125 = 10 : 8
That is no accident. The dimensions of the lowest-cost crate are such that any pair of opposite sides costs the same.