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Day 4: As a landscaper, one of your clients wants a rectangular garden in which the length is five feet
more than twice the width. The perimeter of the garden is 82 feet. In square feet, what is the area of
the garden?

Respuesta :

Answer:

The Area of Rectangular Garden is 1044  feet²    

Step-by-step explanation:

According to question

The perimeter of the garden = 82 ft

Let the length be L ft

The width be W ft

Now as per question

L = 5 + ( 2× W )

∵ Perimeter of Rectangle = 2 × ( Length + Width )

Or , Perimeter of Rectangle = 2 × ( L+ W )

Or, 82 = 2 × ( L+ W )

Or,  82 = 2 × [ 5 + ( 2 ×W ) + W ) ]

Or,  82 = 2 × ( 5 +3W )

Or,  41 = 5 + 3W

Or, 41 - 5 = 3W

So, 3W= 36

∴    W = [tex]\frac{36}{3}[/tex] = 12 feet

I.e Width = 12 feet

And L = 5 + ( 2× W )

Or, Length = 5 + 24 = 29 feet

Now The Area of Rectangle = Length × width

So, The Area of Rectangle = 29 ft × 36 ft

The Area of Rectangle is 1044 feet²

Hence The Area of Rectangular Garden is 1044  feet²        Answer

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