[tex]\boxed{f(x)+g(x)=\frac{1}{x}-x-\frac{23}{6}}[/tex]
Explanation:
We are given two functions:
[tex]f(x)=\frac{1}{4}x-4 \\ \\ g(x)=\frac{1}{6}-x[/tex]
So, we have to find [tex]f(x)+g(x)[/tex] which is the sum of these two functions:
[tex]f(x)+g(x)=\frac{1}{x}-4+\frac{1}{6}-x \\ \\ \\ Let's \ call \ h(x)=f(x)+g(x) \\ \\ Simplifying: \\ \\ h(x)=\left(\frac{1}{x}-x)+(-4+\frac{1}{6}) \\ \\ \\ \\[/tex]
[tex]Finally: \\ \\ \boxed{f(x)+g(x)=\frac{1}{x}-x-\frac{23}{6}}[/tex]
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