[tex]\boxed{x=12 \ and \ x=2}[/tex]
In this exercise, we have the following equation:
[tex]x^2-14x+49=25[/tex]
We can write this Quadratic Equation in Standard Form as follows:
[tex]x^2-14x+49=25 \\ \\ Subtract \ 25 \ from \ both \ sides: \\ \\ x^2-14x+49-25=25-25 \\ \\ x^2-14x+24=0 \\ \\[/tex]
So this is a Non-perfect Square Trinomial. To factor out this, let's choose two numbers such that:
Those numbers are:
So we can write this as:
[tex]x^2 + (a + b)x + ab=(x + a)(x + b) \\ \\ a=-12 \\ b=-2 \\ \\ x^2-14x+24=(x-12)(x-2)=0 \\ \\ So \ the \ solutions \ are: \\ \\ \boxed{x=12 \ and \ x=2}[/tex]
Quadratic Ffrmua: https://brainly.com/question/10188317
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