Answer:
The answer to your question is: 118 ml of KOH
Explanation:
Data
volume KOH = ?
[KOH] = 0.985 M
volume HNO3 = 50 ml = 0.05 l
[HNO3] = 2.32 M
Reaction
KOH + HNO3 ⇒ KNO3 + H2O
Formula
Molarity = moles / volume
Process
moles of HNO3 = 2.32 x 0.05 l
= 0.116
From the equation we know that the proportion KOH : HNO3 = 1 : 1
then,
1 mol of KOH ---------------- 1 mol of HNO3
x --------------- 0.116 mol of HNO3
x = (0.116 x 1)/ 1
x = 0.116 moles of KOH
Now, calculate volume of KOH
Volume of KOH = moles of KOH / molarity
Volume of KOH = 0.116 / 0.985
= 0.118 l of KOH or 118 ml
