The final equation of line that passes through (9, 0) AND (0, -6) is:
[tex]y=\frac{2}{3}x-6[/tex]
Further explanation:
The general form of equation of line is:
[tex]y=mx+b[/tex]
Given
(x1,y1) = (9,0)
(x2,y2) = (0, -6)
We have to find the slope first:
[tex]m=\frac{y_2-y_1}{x_2-x_1}\\= \frac{-6-0}{0-9}\\=\frac{-6}{-9}\\=\frac{2}{3}[/tex]
Putting the value of slope in general form
[tex]y=\frac{2}{3}x+b[/tex]
To find the value of b, we have to put a point in the equation
Putting (9,0) in equation
[tex]0=\frac{2}{3}(9)+b\\0=2*3+b\\0=6+b\\b=-6[/tex]
Putting the values of b and m in general form
The final equation of line that passes through (9, 0) AND (0, -6) is:
[tex]y=\frac{2}{3}x-6[/tex]
Keywords: Equation of line, Pount-slope form
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