Answer:
0.906 N
Explanation:
Formula for magnetic force acting on current carrying cable:
[tex] F = IBLsin(\theta) [/tex]
Where I = 345A is the current in the wire, B = [tex]5.6*10^{-5} T[/tex] is the magnetic magnitude generated by Earth. L = 46.9 m is the cable length. [tex]\theta = 88.2^o[/tex] is the angle between vector B and cable direction.
[tex] F = 345*5.6*10^{-5}*46.9*sin(88.2^o) [/tex]
[tex] F = 0.906 N[/tex]
