The value of (x-y) is 16
Further explanation:
We have to use the given values to find the value
Given
[tex]x+y=4\\and\\x^2-y^2=64[/tex]
We will use:
[tex]x^2-y^2=64[/tex]
Simplifying by using: [tex]x^2-y^2=(x+y)(x-y)[/tex]
So,
[tex](x+y)(x-y)=64[/tex]
As we know that x+y=4
Putting the value in equation
[tex](4)(x-y)=64[/tex]
Dividing both sides by 4
[tex]\frac{4(x-y)}{4}=\frac{64}{4}\\x-y=16[/tex]
The value of (x-y) is 16
Keywords: Algebraic formulas, Simplification
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