Answer with Explanation:
We are given that
Mass of box=35 kg
Coefficient of static friction between box and truck bed=0.202
Acceleration due to gravity=[tex]9.8 m/s^2[/tex]
a.We have to find the force by which the box accelerates forward.
Force by which box accelerates=[tex]\mu mg=0.202\times 9.8\times 35[/tex]
Force by which box accelerates=[tex]62.286 N[/tex]
b.We have to find the maximum acceleration can the truck have before the box slides.
Force =friction force
[tex]ma=\mu mg[/tex]
[tex]a=\mu g=9.8\times 0.202=1.9796 m/s^2[/tex]
Hence, the truck can have maximum acceleration before the box slide=[tex]1.9796 m/s^2[/tex]
