Answer:
0.0159
Step-by-step explanation:
Given that a common practice of airline companies is to sell more tickets for a particular flight than there are seats on the plane, because customers who buy tickets do not always show up for the flight.
Here if X is the no of persons that do not show up, then X is binomial as each trial is independent with p = 0.04 and n =150 (no of tickets sold)
The plane is overbooked if more than 150 show up
i.e. less than 2 do not show up
Hence the probability that the airline overbooked this flight
=[tex]P(X<2) = P(x=0,1,2)\\\\=\Sigma _{i=0} ^2 150Ci (0.04)^i (1-0.04)^{150-i} \\=0.0159[/tex]
