In rabbits, the homozygous CC is normal, Cc results in deformed legs, and cc results in very short legs. The genotype BB produces black fur, Bb brown fur, and bb white fur. If a cross is made between brown rabbits with deformed legs and white rabbits with deformed legs, what percentage of the offspring would be expected to have deformed legs and white fur

The probability of offspring having the bb genotype is 1/2*1 = 1/2; there is a 1/2 probability that the BbCc parent passes on the b allele, while the second parent will only ever contribute the b allele.

The probability of getting the Cc genotype is 2*1/2*1/2 = 1/2; from either parent, there is a 1/2 probability that either C or c is passed, and we multiply by 2 to account for the ways they can be inherited. (In other words, parent A can pass on C and parent B can pass on c, and vice versa.)

Leg length and fur color are inherited independently of one another, so the probability of observing offspring with the bbCc genotype is 1/2*1/2 = 1/4.

PiaDeveau PiaDeveau · Answer 2 · 2021-12-08T07:38:43+01:00

Probability of Total number of same genotype bbCc is 25%

Given that;

Normal legs = CC

Deformed legs = Cc

Very short legs = cc

Black fur = BB

Brown fur = Bb

White fur = bb

Computation;

All cross breeding results are;

BbCC, BbCc, bbCC, bbCc , BbCc, Bbcc, bbCc, bbcc

Total number of results = 8

Total number of same genotype bbCc = 2

Probability of Total number of same genotype bbCc = [2/8]100

Probability of Total number of same genotype bbCc = 25%

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