Answer:
The archerfish must spit at a minimum speed of [tex]3.43m/s[/tex] at an angle of [tex]69.14\°[/tex] above the horizontal.
Explanation:
Hi
First of all, we need to find the angle above the horizontal at which the archerfish must spit, as we can see in the attachment this angle is [tex]\Theta = 69.14\°[/tex].
Then we use the formula [tex]h=\frac{v_{0}^{2}sin^{2} \Theta}{2g}[/tex], as we clear it for [tex]v_{0}[/tex], we obtain, [tex]v_{0}=\frac{\sqrt{2gh} }{sin\Theta}=\frac{\sqrt{2(9.8m/s^{2})(0.525m)} }{sin(69.14\°)}=3.43m/s[/tex], therefore the archerfish must spit at a minimum speed of [tex]3.43m/s[/tex] at an angle of [tex]69.14\°[/tex] above the horizontal.
