Respuesta :
Answer:
B) True.
Explanation:
In this exercise to answer the statements we must calculate the force on the earth by the two bodies.
In both cases, the law of universal gravitation describes the process.
F = G m₁ m₂ / r²
Let's calculate each force
- bodies Moon - Earth
Let's call m₁ the mass of the earth (m₁ = me), m₂ the mass of the moon (m₂ = m), the distance from the earth to the moon is r₁ = 3.84 10⁸m and the radius of the earth is re. The force on the tide that is a body on the surface of the Earth have a distance
R₁ = r₁ -re
R₁ = 3.84 10⁸ - 6.37 10⁶
R₁ = 3.77 10⁸ m
Let's calculate
F₁ = G me m / R₁²
F₁ = (G me) 7.36 10²² / (3.77 10⁸)²
F₁ = (G me) 5.2 10⁵
- bodies Earth -Sun
Let's call the mass of the sun M (m2 = M) the distance from the sun to the earth is 1.5 10¹¹ m, so the distance to the surface of the earth
R₂ = r₂ - re
R₂ = 1.5 10¹¹ - 6.37 10⁶
R₂ = 1.5 10¹¹ m
The radius of the earth is too small compared to the earth-sun distance
Let's calculate
F₂ = G me M / R₂²
F₂ = (G me) 1.99 10³⁰ / (1.5 10¹¹)²
F₂ = (G me) 8.8 10⁷
Let's see the statements:
A) False. It´s oppsote
B) True. In the previous part it has a differentiated 10² orders of magnitude
C) False. We saw that they are very different
Answer:
B. The force exerted on Earth by the Sun is stronger than the corresponding force exerted by the Moon.
Explanation:
The gravitational force between two planets is given by the following formula:
[tex]F = G \cdot \frac{m\cdot M}{r^{2}}[/tex]
Where:
[tex]G[/tex] - Gravitational constant.
[tex]m[/tex], [tex]M[/tex] - Masses of planets.
[tex]r[/tex] - Distance between planets.
The following is the description of the forces exerted on Earth as both as by the Sun and by the Moon:
Earth - Moon
[tex]F = \left(6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}} \right)\cdot \left[\frac{(5.972\times 10^{24}\,kg)\cdot (7.348\times 10^{22}\,kg)}{(384000000\,m)^{2}} \right][/tex]
[tex]F = 1.986\times 10^{20}\,N[/tex]
Earth - Sun
[tex]F = \left(6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}} \right)\cdot \left[\frac{(5.972\times 10^{24}\,kg)\cdot (1.99\times 10^{30}\,kg)}{(1.5\times 10^{11}\,m)^{2}} \right][/tex]
[tex]F = 3.525\times 10^{22}\,N[/tex]
The force exerted on Earth by the Sun is greater than the force by the Moon. Hence, the answer is B.