Answer:
The equation for the line that passes through the points (4,8) and (6,2)
is y + 3 x -20 = 0
Step-by-step explanation:
Here, the given points are (4,8) and (6,2)
So, the slope of the equation joining two points is [tex]m = \frac{y_2- y_1}{x_2 - x_1} = \frac{2-8}{6-4} =\frac{-6}{2} = -3\\[/tex]
⇒Slope of the given line is m = -3
Now, by POINT SLOPE FORMULA:
Equation of a line is (y - y0) = m (x-x0)
Here, equation of the line with (x0, y0) = (6,2) is
y - 2 = (-3)(x - 6)
or, y -2 = -3x + 18
⇒ y+ 3x -20 = 0
Hence, the equation for the line that passes through the points (4,8) and (6,2) is y+ 3x -20 = 0
