Respuesta :
Answer:
The mass of the electron is [tex]8.7 \times 10^{-31} \mathrm{kg}[/tex]
Explanation:
Photoelectric effect is given by
[tex]\mathrm{hv}=\mathrm{hv}_{0}+1 / 2\left(\mathrm{mv}^{2}\right)[/tex]
where ν0 = threshold frequency of given metal = [tex]1.40 \times 10^{5} \mathrm{ms}^{-1}[/tex]
ν = given radiation = [tex]1.8 \times 10^{15}[/tex]
v = velocity of emitted electron = given =[tex]7.79 \times 105 \mathrm{ms}^{-1}[/tex]
m = required mass of electron
h = Plank’s constant = [tex]6.6 \times 10^{-34}[/tex]
Substituting the values in the formula
[tex]\mathrm{h}\left(\mathrm{v}-\mathrm{v}_{0}\right)=1 / 2\left(\mathrm{mv}^{2}\right)[/tex]
[tex]6.6 \times 10^{-34}\left(1.8 \times 10^{15}-1.40 \times 10^{5}\right)=1 / 2\left(\mathrm{m} \times(7.79 \times 105)^{2}\right)[/tex]
Solving this we get m = [tex]8.7 \times 10^{-31} \mathrm{kg}[/tex]
which is the mass of the electron.
