A 16.0 kg canoe moving to the left at 12.5 m/s makes an elastic head-on collision with a 14.0 kg raft moving to the right at 16.0 m/s. After the colli-
sion, the raft moves to the left at 14.4 m/s. What is the final velocity of the canoe? Disregard any effects of the water.
O 14.1 m/s to the right
O 13.9 m/s to the right
14.1 ms/to the left
13.9 m/s to the left

Respuesta :

Answer:

Option A

14.1 m/s to the right

Explanation:

From equation of conservation of linear momentum

[tex]M_rV_r+M_cV_c=M_rV_{rf}+M_cV_{cf}[/tex] where [tex]M_r[/tex] and [tex]M_c[/tex] are masses of raft and canoes respectively, [tex]V_r[/tex] and [tex]V_{rf}[/tex] are initial and final velocities of raft respectively, [tex]V_c[/tex] and [tex]V_{cf}[/tex] are the initial and final velocities of canoe respectively.

Re-arranging and making [tex]V_{cf}[/tex] the subject of the formula

[tex]V_{cf}=\frac {M_rV_r+M_cV_c-M_rV_{rf}}{M_c}[/tex]

Substituting the figures given

[tex]V_{cf}=\frac {(14 kg *16 m/s)+(16 kg*-12.5 m/s)-(14 Kg*-14.4 m/s)}{16 Kg}[/tex]

=14.1 m/s towards right

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