Answer:
13.6565mm of Hg
Explanation:
We only need to use the from Hagen poiseuille equation to be able to find the pressure change. That is
[tex]\Delta P = \frac{128\eta LQ}{\pi D^4}[/tex]
Once the equation is defined, we clear based on the pressure and replace
[tex]\frac{\Delta P_2}{\Delta P_1} = (\frac{\eta_2}{\eta_1})(\frac{D_1}{D_2})^4[/tex]
[tex]\frac{\Delta P_2}{\Delta P_1} = \frac{2.8*10^{-3}}{2.5*10^{-3}}(\frac{D_1}{(1-0.1)D_1})^4[/tex]
[tex]\frac{\Delta P_2}{8}=1.707[/tex]
Finally we have,
[tex]\Delta P_2 = 13.6565mm of Hg[/tex]
