[tex]\boxed{y=\frac{16}{3}}[/tex]
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The complete question states:
y varies directly as x. If y=-12 when x=9 find y when x=-4?
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If y varies directly as x, we can write a relationship between these two variables as follows:
[tex]y=kx \\ \\ Where \ k \ is \ a \ non-zero \ real \ constant[/tex]
Here we know that:
[tex]y=-12 \ when \ x=9[/tex]
So we can calculate [tex]k[/tex]
[tex]y=kx \\ \\ Solving \ for \ k: \\ \\ k=\frac{y}{x} \\ \\ Substituting \ values: \\ \\ k=\frac{-12}{9} \\ \\ k=-\frac{4}{3}[/tex]
Finally, our result is:
[tex]y=-\frac{4}{3}x \\ \\ \\ If \ x=-4, then: \\ \\ y=-\frac{4}{3}(-4) \\ \\ \boxed{y=\frac{16}{3}}[/tex]
Relationship between variables: https://brainly.com/question/12809482
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