Answer:
pH = 6,951
Explanation:
The neutral form of aspartic acid is in its isolectric point. For aspartic acid the isoelectric point is the average of pka1 and pka2, thus:
[tex]pH =\frac{1}{2} (3,900+1,990)[/tex]= 2,945
The addition of stoichiometric amounts of NaOH at the first equivalence point will increase the pH at average of pka2 and pka3 thus:
[tex]pH = \frac{1}{2} (3,900+10,002)[/tex]= 6,951
Thus, pH at the first equivalence point is 6,951
I hope it helps!
