Consider six 0.0001 m aqueous solutions of aspirin, nacl, mgcl2, dextrose, mannitol and mgso4. which solution has the lowest vapor pressure?

Respuesta :

Answer:

The solution of [tex]MgCl_2[/tex] will have the lower vapor pressure.

Explanation:

Hi, due to the Colligative properties the vapor pressure of a solution decreases proportional to the mols of ions or molecules disolved in it.

So, the more molecules you disolve in a solvent, the more its vapor pressure decreases.

Now, all six solutes are in the same amount of molecules (same molarity) but:

1) [tex]NaCl[/tex] and [tex]MgSO_4[/tex] when mixed on water disociate:

[tex]NaCl \longrightarrow Na^+ +Cl^-[/tex]

[tex]MgSO_4 \longrightarrow Mg^{+2} + SO_4^{-2}[/tex]

Each molecule gives two new molecules two the solution so this two solutions would have a concentraion of 2*0.0001 m= 0.0002 m

2) Aspirin, dextrose and mannitol when mixed in water, don't disociate so they concentration would remain 0.0001 m.

3) At last [tex]MgCl_2[/tex] disociates giving 3 molecules:

[tex]MgCl_2 \longrightarrow Mg^{+2} + 2 Cl^-[/tex]

Its concentration would be 3*0.0001 m = 0.0003 m

Being said that the more molecules you disolve the lower the vapor pressure, the solution of [tex]MgCl_2[/tex] will have the lower vapor pressure.

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