Answer:
[tex]\Delta f= 144.71KHz[/tex]
Explanation:
We define two formulas. Firt for the stationary object and then for the shpo,
The frequency formula for the stationary is,
[tex]f_{Lr}=\frac{V+V_w}{V}f^1\\f_{S}=\frac{V}{V-V_w}f^2[/tex]
We need to find the difference or the rate of the relevant frequencies, that is
[tex]\Delta f= f_{Lr}-f_S\\\Delta=f\frac{2V_w}{V-V_w}[/tex]
With the dates that we have, we only make a substitution,
[tex]f=22 KHz\\V_w = 4.95m/s\\V= 1510m/s[/tex]
[tex]\Delta f= (22.0KHz)(\frac{2(4.95)}{1510-4.95})[/tex]
[tex]\delta f= 144.71KHz[/tex]
