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In Trial III, a different, looser, spring is used; its force constant is 23.1 N/m. The suspended mass is the same as the one in Trial I: 0.400 kg. Theoretically speaking, what period of oscillations should we expect, based on these values of k and m? Enter your answer in seconds with two significant figures.

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Answer:

T=0.827s

Explanation:

The period of a spring can be calculated with the equation

[tex]T=2\pi w[/tex]

But we know as well that w is given by,

[tex]w=\sqrt{\frac{k}{m}}[/tex]

Replacing,

[tex]w=\frac{2\pi}{T}= \sqrt{\frac{k}{m}}\\T=2\pi\sqrt{\frac{k}{m}}\\T=2\pi\sqrt{\frac{0.4}{23.1}}[/tex]

So we have that

[tex]T=0.827s[/tex]

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