Respuesta :
Answer:
-100
-10, 10
Step-by-step explanation:
Let the smaller number be x.
Then the larger number is x + 20.
The product is x(x + 20).
Now you can write the function
y = x(x + 20)
y = x^2 + 20x
Take the first derivative of y with respect to x.
y' = 2x + 20
Set the first derivative equal to zero to find the x value for the minimum value of the function.
2x + 20 = 0
2x = -20
x = -10
The minimum value of the function occurs at x = -10. -10 is one of the two numbers.
y = x^2 + 20x
For x = -10,
y = (-10)^2 + 20(-10)
y = 100 - 200
y = -100
The minimum value of the product is -100.
x = -10
x + 20 = -10 + 20 = 10
The numbers are -10 and 10.
If you have not learned derivatives yet, then plot the function
y = x^2 + 20x
Now look at the graph and find the minimum y value and the x value at which it occurs.
The minimum y value is -100. That is the minimum product you are looking for.
The x value of the minimum function value is x = -10.
Then x + 20 = -10 + 20 = 10.
The numbers are -10 and 10.
We want to find two numbers such that their difference is 20 and whose product is minimized.
The pair of numbers is 10 and -10.
Let's define our two numbers as A and B.
Such that A < B.
We want the difference to be equal to 20, then we have:
B - A = 20.
The product between these two numbers is written as:
P = A*B
From the first equation, we can write:
B = 20 + A
Now we can replace that on the product equation to get:
P = A*(20 + A) = 20*A + A^2
Now we want to minimize this, notice that this is a quadratic polynomial, thus the minimum is at the vertex.
For a general quadratic polynomial.
y = a*x^2 + b*x + c
The vertex is at:
x = -b/2a
So in our case, P = 20*A + A^2
The vertex is at:
A = -20/(2*1) = -10
Then we have A = -10
To find the value of B we use the first equation:
B - A = 20
B = 20 + A = 20 + (-10) = 10
Then the pair of numbers is A = -10 and B = 10, and the product is:
P = 10*-10 = -100.
If you want to learn more, you can read:
https://brainly.com/question/2866380