Answer:
0.667 per day.
Explanation:
Our values here are
[tex]Q=10m^3/dV_p=15m^3\\V_{cstr}=60m^3\\c_p=2500mg/L\\c_{cstr}=500mg/L[/tex]
Degradation constant=k and is unknown.
We calculate the concentration through the formula,
[tex]cc_{cstr} =\frac{c_{in}}{1+K(V/Q)} \\cc_{cstr}=\frac{c_p}{1+K*\frac{V_{csrt}}{Q}}[/tex]
Replacing values we have
[tex]1+k(\frac{60}{10})=\frac{2500}{500}\\1+k=5\\K(6)=5-1\\K(6)=4\\K=2/3\\K=0.667/day[/tex]
That is the degradation constant of Z-contaminant
