Answer:
[tex]m_{H}=8.89 g[/tex]
Explanation:
To balance the equation:
1) Asume 1 mol of N2 :
[tex] N_2 (g) + __ H_2 (g) \longrightarrow __ NH_3 (g)[/tex]
2) Balance the nitrogen:
[tex] N_2 (g) + __ H_2 (g) \longrightarrow 2 NH_3 (g)[/tex]
3) Balance the hydrogen:
[tex] N_2 (g) + 3 H_2 (g) \longrightarrow 2 NH_3 (g)[/tex]
To calculate the hydrogen:
[tex]M_{am}= molecular weight of ammonia[/tex]
[tex]M_{am}= 14+3*1=17 g/mol[/tex]
[tex]n_{am}= mol of ammonia[/tex]
[tex]n_{am}= \frac{50g}{17 g/mol}=2.94 mol[/tex]
Due to the equation you need 3 mol of hydrogen per 2 mol of ammonia:
[tex]n_{H}= 2.94 mol \frac{3}{2}=4.41 mol[/tex]
[tex]m_{H}=2.016 \frac{g}{mol}*4.41 mol=8.89 g[/tex]
