Answer: 0.0746 grams of hydrogen
Explanation:
To calculate the mass of hydrogen :
(Vapor pressure of water is 23.78 mmHg at 25 ∘C )
[tex]2H^+(aq)+Zn(s)\rightarrow H_2(g)+Zn^{2+}(aq)[/tex]
According to avogadro's law, 1 mole of every substance occupies 22.4 L at NTP, weighs equal to the molecular mass and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
According to the ideal gas equation:
[tex]PV=nRT[/tex]
P = Total Pressure = 752 mm Hg
pressure of hydrogen = Total Pressure - Vapor pressure of water =  (752 -23.78 )mm Hg = 728.22 mm Hg =  0.958 atm  (760mmHg=1atm)
V= Volume of the gas = 0.953 L
T= Temperature of the gas = 25°C = 298 K Â
R= Gas constant = 0.0821 atmL/K mol
n= moles of gas= ?
[tex]n=\frac{PV}{RT}=\frac{0.958\times 0.953}0.0821\times 298}=0.0373moles[/tex]
Mass of [tex]H_2=moles\tims {\text {molar mass}}=0.0373mol\times 22g/mol=0.0746g[/tex]
Thus 0.0746 grams of hydrogen is collected.