0.832 M is the molarity of the vinegar solution whose volume is 25mL.
How we calculate the molarity?
Molarity of vinegar will be calculated by using the below formulas:
M₁V₁ = M₂V₂, where
M₁ = molarity of NaOH = 2.293 M
V₁ = volume of NaOH = 9.08mL = 0.00908L
M₂ = molarity of vinegar = to find?
V₂ = volume of vinegar = 25mL = 0.025L
On putting all these value in the above equation and we calculate for the value of M₂ as:
M₂ = (2.293 × 0.00908) / 0.025 = 0.832 M
Hence, 0.832 M is the molarity.
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