Answer:
μs = 0.75
μk = 0.58
Explanation:
From a force diagram:
[tex]m*g*sin \theta - Ff=m*a[/tex] (1)
[tex]N-m*g*cos \theta = 0[/tex] (2)
When it starts slipping, friction force is the maximum and acceleration is 0. Replacing these conditions on (1):
[tex]m*g*sin \theta - \mu*m*g*cos \theta=0[/tex] Solving for μs:
[tex]\mu=tan \theta[/tex]
μs = tan 36.7° = 0.75
When it moves at constant speed, friction force is kinetic friction and acceleration is 0. With these conditions the coefficient is:
μk = tan 30.1° = 0.58