Answer:
The distance in meters of the disk move during 41s is
x= 73.41m
Explanation:
The velocity angular is 1.5 rev/s
[tex]1.5\frac{rev}{s} \frac{41s}{1}=61.5 rev[/tex]
The revolutions here are the number of rounds so to determinate how far in lineal distance
[tex]x_{d}=N*\pi *r\\r=19cm \frac{1m}{100cm}=0.19m\\N=61.5\\x_{d}=61.5*2\pi *0.19m\\x_{d}=73.41m[/tex]
The distance in meters is  x=73.41m
