Respuesta :
Answer:
[tex]2Al+6HCl\rightarrow 2AlCl_3+3H_2[/tex]
5.39 g
Explanation:
The balanced equation for the reaction of aluminum with hydrochloric acid is shown below as:-
[tex]2Al+6HCl\rightarrow 2AlCl_3+3H_2[/tex]
Given,
Pressure = 0.750 atm
Temperature = 30.0 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T = (30.0 + 273.15) K = 303.15 K
T = 303.15 K
Volume = 10.0 L
Using ideal gas equation as:
PV=nRT
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L.atm/K.mol
Applying the equation as:
0.750 atm × 10.0 L = n × 0.0821 L.atm/K.mol × 303.15 K
⇒n = 0.3013 moles
Moles of hydrogen obtained = 0.3013 moles
From the reaction,
3 moles of hydrogen gas are furnished when 2 moles of aluminum is consumed.
Also,
1 mole of hydrogen gas are furnished when [tex]\frac{2}{3}[/tex] mole of aluminum is consumed.
Thus,
0.3013 mole of hydrogen gas are furnished when [tex]\frac{2}{3}\times 0.3013[/tex] mole of aluminum is consumed.
Moles of aluminum consumed = 0.2 moles
Also, Molar mass of aluminum = 26.981539 g/mol
So, Mass = Moles*Molar mass = 0.2 moles*26.981539 g/mol = 5.39 g
