Respuesta :
5 Halloween bags containing 14 bars and 21 gum pieces, 7 Halloween bags containing 10 bars and 15 gum pieces and 35 bags containing 2 bars and 3 gum pieces can be created using 70 Milky Way bars and 105 pieces of bubble gum.
Solution:
Mrs Cohan is making Halloween bags for her party.
Number of Milky Way bars with Mrs Cohan = 70
Number of bubble gum pieces with Mrs Cohan = 105
We need to distribute 70 bars and 105 bubble gum pieces in each bag
On factorizing 70 we get
[tex]70=7 \times 5 \times 2[/tex]
On factorizing 105 we get
[tex]105=7 \times 5 \times 3[/tex]
The common factors of 70 and 105 are 5, 7 and 35
So 70 bars and 105 bubble gum pieces can be equally distributed among 5 bags, 7 bags and 35 bags.
⇒ Number of milky bar in each bag when 5 bags are created [tex]=\frac{70}{5}=14[/tex]
⇒ Number of bubble gum pieces in each bag when 5 bags are created [tex]=\frac{105}{5}=21[/tex]
⇒ Number of milky bar in each bag when 7 bags are created [tex]=\frac{70}{7}=10[/tex]
⇒ Number of bubble gum pieces in each bag when 5 bags are created [tex]=\frac{105}{7}=15[/tex]
⇒ Number of milky bar in each bag when 35 bags are created [tex]=\frac{70}{35}=2[/tex]
⇒ Number of bubble gum pieces in each bag when 35 bags are created [tex]=\frac{105}{35}=3[/tex]
Hence ⇒ 5 Halloween bags containing 14 bars and 21 gum pieces
⇒ 7 Halloween bags containing 10 bars and 15 gum pieces
⇒ 35 bags containing 2 bars and 3 gum pieces can be created using 70 Milky Way bars and 105 pieces of bubble gum.
