Answer:
1) For, m = 3/4 , (0,4) , 4y - 16 - 3x = 0 is the equation of line.
2) For, m = 4 , (-2,-5) , y - 4x - 4 = 0 is the equation of line.
3) For, m = -1/3 , (4,-1) , x + 3y -1 = 0 is the equation of line.
Step-by-step explanation:
If m is the slope and (x0,y0) is the point on any given equation, then
by POINT SLOPE FORMULA:
The line equation is given as (y - y0) = m (x -x0)
Now , here:
1) m = 3/4 , (x0, y0) = (0.4)
So,, the equation of line is [tex](y-4) = \frac{3}{4} (x-0)\\or, 4(y-4) = 3x[/tex]
on simplification, 4y - 16 - 3x = 0 is the equation of line.
2) m = 4 , (x0, y0) = (-2.-5)
So,, the equation of line is [tex](y-(-5)) = 4 \times (x-(-2))\\or, (y+4) = 4(x+2)[/tex]
on simplification, y - 4x - 4 = 0 is the equation of line.
3) m = -1/3 , (x0, y0) = (4, -1)
So,, the equation of line is [tex](y-(-1)) = \frac{-1}{3} (x-4)\\or, 3(y+1) = -(x-4)[/tex]
on simplification, x + 3y -1 = 0 is the equation of line.
