Hydrogen has four emission lines in the visible light range : violet, blue, green, and red. Match the color of the emission line to its electron transition.

A.n = 4 → n = 2
B.n = 3 → n = 2
C.n = 6 → n = 2
D.n = 5 → n = 2

The transitions involved are all to energy level n=2 from higher energy levels. The energy of the emission line correspondingly will reflect a higher energy the greater n is and the color of the emission spectra line will likewise correspond to higher energy. Since the energy of the colors given follow the sequence:

Eviolet ⇒ E blue ⇒ Egreen ⇒ E red

6 to 2 5 to 2 4 to 2 3 to 2

Remember that the the energy and the frequency of the visible colors is greatest for violet and lowest for red. That is why we refer to ultraviolet light being highly energetic ( sunburn) and infrared gogles which are used for low energy night vision ( the ultra and infra mean beyond visible spectrum)

Hydrogen has four emission lines in the visible light range : violet, blue, green, and red. Match the color of the emission line to its electron transition.A.n = 4 → n = 2 B.n = 3 → n = 2C.n = 6 → n = 2D.n = 5 → n = 2

Respuesta :

Eviolet ⇒ E blue ⇒ Egreen ⇒ E red

6 to 2 5 to 2 4 to 2 3 to 2

Otras preguntas

Hydrogen has four emission lines in the visible light range : violet, blue, green, and red. Match the color of the emission line to its electron transition.

A.n = 4 → n = 2
B.n = 3 → n = 2
C.n = 6 → n = 2
D.n = 5 → n = 2