Answer:
[tex]K E = 44.98\ J[/tex]
Explanation:
given,
mass of hoop = 2.75 Kg
horizontal speed = 4.5 m/s
angle with horizontal = 25°
m g l sin θ = m ( v² - u² )
g l sin θ = ( v² - u² )
9.8 x 3 x sin 25° = ( v² - 4.5² )
12.425 = v² - 20.25
v² = 32.675
v = 5.72 m/s
Rotational
[tex]K E = \dfrac {1}{2}I\omega^2[/tex]
[tex]K E = \dfrac {1}{2}\ mR^2\omega^2[/tex]
[tex]K E = \dfrac {1}{2}\ mv^2[/tex]
[tex]K E = \dfrac {1}{2}\ 2.75 \times 5.72^2[/tex]
[tex]K E = 44.98\ J[/tex]
