For this case we have that by definition, the equation of a line of the slope-intersection form is given by:
[tex]y = mx + b[/tex]
Where:
m: It's the slope
b: It is the cut-off point with the y axis
The slope is found using the following formula:
[tex]m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}[/tex]
According to the graph we have the following points:
[tex](x_ {1}, y_ {1}): (-2, -3)\\(x_ {2}, y_ {2}) :( 3, -3)[/tex]
Substituting we have:
[tex]m = \frac {-3 - (- 3)} {3 - (- 2)} = \frac {-3 + 3} {3 + 2} = \frac {0} {5} = 0[/tex]
Therefore, the line is of the form:
[tex]y = 0x + b\\y = b[/tex]
We find "b" replacing the coordinate "y" of a point:
[tex]-3 = b[/tex]
Thus, the equation is:
[tex]y = -3[/tex]
Answer:
[tex]y = -3[/tex]
