Answer:
[tex]A) (1.2)^{2} = 1.44[/tex]
[tex]B)2^ 3+17-(3\times 4) = 13[/tex]
[tex]C)\frac{(9)^2}{(3)^3} = 3[/tex]
Step-by-step explanation:
Here, the given expressions are:
A) [tex](1.2)^{2}[/tex]
Solving this, we get
[tex](1.2)^{2} = 1.2 \times 1.2 = 1.44[/tex]
⇒[tex](1.2)^{2} = 1.44[/tex]
B) [tex]2^ 3+17-(3\times 4)[/tex]
Now, solving this, we get
[tex]2^ 3+17-(3\times 4) = (2 \times 2 \times2) + (17 -12)\\=8 + 5 = 13[/tex]
⇒[tex]2^ 3+17-(3\times 4) = 13[/tex]
C) [tex]\frac{(9)^2}{(3)^3}[/tex]
Simplifying this, we get
[tex]\frac{(9)^2}{(3)^3} = \frac{(9\times9)}{(3 \times 3\times3)} = 3[/tex]
⇒ [tex]\frac{(9)^2}{(3)^3} = 3[/tex]
