Answer:
[tex]v=\sqrt{ 2 (g sin\theta- f/m) d}[/tex]
Explanation:
Given that
Mass = m
Height = h
Length = d
Angle = θ
Friction force = f
When block slides downward then friction force will act upwards
The force due to gravity along inline plane
Fg= mg sinθ
Lets 'a' is the acceleration
From Newtons law
mg sinθ - f = m a
a= (g sinθ - f/m)
Given that initial speed u= o ,lets v is final speed
v²=u²+ 2 a s
v²=2 x (g sinθ - f/m) x d
[tex]v=\sqrt{ 2 (g sin\theta- f/m) d}[/tex]
