Answer:
We accept the null hypothesis and conclude that voltage for these networks is 232 V.
Step-by-step explanation:
We are given the following in the question: Â
Population mean, μ = 232 V
Sample mean, [tex]\bar{x}[/tex] = 231.5 V
Sample size, n = 66
Sample standard deviation, s = 2.19 V
Alpha, α = 0.05
First, we design the null and the alternate hypothesis
[tex]H_{0}: \mu = 232\\H_A: \mu \neq 232[/tex]
We use Two-tailed t test to perform this hypothesis.
Formula:
[tex]t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n-1}} }[/tex] Putting all the values, we have
[tex]t_{stat} = \displaystyle\frac{231.5- 232}{\frac{2.19}{\sqrt{66}} } = -1.8548[/tex]
Now,
[tex]t_{critical} \text{ at 0.05 level of significance, 9 degree of freedom } = \pm 1.9971[/tex]
Since, Â Â Â Â Â Â Â
[tex]|t_{stat}| > |t_{critical}|[/tex]
We accept the null hypothesis and conclude that voltage for these networks is 232 V.