Respuesta :
Answer:
(-16, 0) and (0,-12) are exactly two points on the graph of the given equation.
Step-by-step explanation:
Here, the given expression is : [tex]M(a) = -\frac{3}{4} a-12[/tex]
Here, let M(a) = b
⇒The equation becomes [tex]b = -\frac{3}{4} a-12[/tex]
Now, check for all the given points for (a,b)
1) FOR (-9,0)
[tex]RHS is -\frac{3}{4} (-9)-12 = -5.25 \neq 0[/tex]
Hence, (-9,0) is NOT on the graph.
2) FOR (-16,0)
Here, LHS = b = 0
and[tex]RHS = -\frac{3}{4} (-16)-12 = 12-12 = 0[/tex]
Hence, LHS = RHS = 0 So, (-16,0) is on the graph.
3) FOR (0,12)
Here, LHS = b = 12
[tex]RHS is -\frac{3}{4} (0)-12 = -12 \neq 12[/tex]
Hence, (0,12) is NOT on the graph.
4) FOR (0,-12)
Here, LHS = b = -12
[tex]RHS is -\frac{3}{4} (0)-12 = -12 [/tex]
and LHS = RHS = -12
Hence, (0,-12) is on the graph.
Hence, (-16, 0) and (0,-12) are exactly two points on the graph of the given equation.
