Answer:
d. 16
Explanation:
Let
Charge on particle=q and mass of particle=m
Radius=2r
Magnetic field=2B
We have to find by what factor the maximum kinetic energy of particle increases.
We know that
Maximum kinetic energy of particle is given by
[tex]K_{max}=\frac{q^2B^2r^2}{2m}[/tex]
Substitute the values then we get
Maximum kinetic energy of particle =[tex]\frac{q(2B)^2(2r)^2}{2m}[/tex]
Maximum kinetic energy of particle =[tex]16\cdot \frac{q^2B^2r^2}{2m}[/tex]
Hence, the maximum kinetic energy of particle increase by 16 when radius is twice and magnetic field is twice strong.
Answer:d.1 6
