Respuesta :

Answer:

[tex]16x {}^{2} - 8x + 1 \\ 16 {x }^{2} - 4x - 4x + 1 \\ (16 {x}^{2} - 4x)( - 4x + 1) \\ 4x(4x - 1) - 1(4x - 1) \\ (4x - 1)(4x - 1)[/tex]

Step-by-step explanation:

[tex]3x + 17x - 6 \\ 3 {x}^{2} - 18x + 1x - 6 \\ (3 {x}^{2} - 18x)(x - 6) \\ 3x(x - 6) + 1(x - 6) \\ (3x + 1)(3x - 6)[/tex]

dis is all I can do and I hope it helps

Q&A Education