Answer:
[tex]\theta = 1.83\°[/tex]
Explanation:
To give solution to this problem we need to apply the second law of Newton.
That is,
[tex]F=mg[/tex]
We make summation of force in Y,
[tex]\sum F_y = 0[/tex]
[tex]2Tsin\theta - mg = 0[/tex]
Solving for [tex]\theta[/tex]
[tex]2tsin\theta = mg[/tex]
[tex]sin\theta = \frac{mg}{2T}[/tex]
[tex]sin\theta = \frac{60*9.8}{2*9200}[/tex]
[tex]sin\theta = 0.0319[/tex]
[tex]\theta = sin^{-1}(0.0319)[/tex]
[tex]\theta = 1.83\°[/tex]
