Answer: 1814400
Step-by-step explanation:
The given letters : O, Z, Q, Y, N, U, Z, J, W, V
Number of letters = 10
Here Z is repeated two times.
The number of permutations of n things , where a are repeated items , b are repeated items and so on :-
[tex]\dfrac{n!}{a!\ b!\ ....}[/tex]
Then, the number of ten letter words can be formed by given 10 letters , where Z is repeated 2 times :-
[tex]\dfrac{10!}{2!}=\dfrac{3628800}{2}=1814400[/tex]
Hence, the number of different 10-letter words (real or imaginary) can be formed =1814400
