Answer:
The time taken is 6.7 min
Explanation:
Using the linear momentum conservation theorem, we have:
[tex]m_1*v_{o1}+m_2*v_{o2}=m_1*v_{f1}+m_2*v_{f2}[/tex]
when she was 60.4m from the shuttle, she has zero speed, so the initial velocity is zero.
[tex]m_1*0+m_2*0=m_1*v_{f1}+m_2*v_{f2}\\m_1*_{f1}=-m_2*v_{f2}\\v_{f1}=-\frac{m_2*v_{f2}}{m_1}\\\\v_{f1}=-\frac{0.886kg*12m/s}{69.8kg}\\\\V_{f1}=-0.15m/s[/tex]
That is 0.15m/s in the opposite direction of the camera.
the time taken to get to the shuttle is given by:
[tex]t=\frac{d}{v_{f1}}\\\\t=\frac{60.4m}{0.15m/s}\\\\t=403s\\t_{min}=403s*\frac{1min}{60s}=6.7min[/tex]
