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Fowle Marketing Research, Inc., bases charges to a client on the assumption that telephone
surveys can be completed in a mean time of 15 minutes or less. If a longer mean survey
time is necessary, a premium rate is charged. A sample of 35 surveys provided the survey
times shown in the file named Fowle. Based upon past studies, the population standard
deviation is assumed known with σ = 4 minutes. Is the premium rate justified?
a. Formulate the null and alternative hypotheses for this application.
b. Compute the value of the test statistic.
c. What is the p-value?
d. At α= .01, what is your conclusion?

Respuesta :

ShyzaSling

Answer:

Answer of A)  H o : u = 15, Ha : u > 15

Answer of B)   z = 2.96

Answer of C)  P = 0.0015

Answer of D) Therefore, We have enough evidence to clearly state that the rate is not justified here.

Explanation:

A)  The mean is equal o the value, however the alternative hypothesis states the complete opposite of the hypothesis.  Hence, Ha : u is greater than 15

B) The working here is as follows:

z = x -u/ a / √n = 17-15 /4/√35 ≈ 2.96

C) The working here is as follows:

P= P (Z . 2.96) = P (Z , - 2.96) = 0.0015

D) Hence, P , 0.05 and Reject H o

This clearly means that the premium rare is not justified.

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b. Compute the value of the test statistic.

Further explanation

σ = 4 minutes

Average telephone survey time (p) = 15 minutes or less

Calculation:

If σ> 15 minutes, then the premium rate is charged

If σ <15 minutes, then the premium rate is not charged

σ: Average survey time (p) = if> 1, then premium rates, if <1, then non-premium rates

σ = 4 minutes

Average survey time = 15 minutes

σ: p =

4: 15 = 0.26

then the tariff is not premium

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statistical value brainly.com/question/13175445

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Details

Class: college

Subject: business

keywords: statistics, surveys, telephone

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